Find the equation of the pair of straight lines passing through the point $(2,1)$ and perpendicular to the pair of lines $4xy + 2x + 6y + 3$
The solution to the above problem is as such :
The required equation is $4(x-2)(y-1)$
$ xy-x-2y+2$
However I couldn’t understand how we can arrive at this solution ? Could you please explain how it’s done ? Thanks !
Best Answer
Note that the equation of the lines represented by the equation $$4xy + 2x + 6y +3=0$$ are given by $2x +3=0$ and $2y +1=0$.
Therefore you can find the equation of the lines perpendicular to these two lines and passing through $(2,1) $.