[Math] Either two sets have the same cardinality, or one has cardinality greater than the other

order-theoryset-theory

This is a problem (10.11) from Munkres, Topology, 2 ed.

Problem: Let $A$ and $B$ be two sets. Using the well-ordering theorem, prove that either they have the same cardinality, or one has cardinality greater than the other.

Well-ordering theorem: If $A$ is a set, there exists an order relation on $A$ that is a well-ordering.

Two sets $A$ and $B$ are said to have the same cardinality if there is a bijection of $A$ with $B$.
Let $A$ and $B$ be two nonempty sets. If there is an injection of $B$ into $A$, but no injection of $A$ into $B$, we say that $A$ has greater cardinality than $B$.

The hint to the problem makes reference to this theorem: Let $J$ and $C$ be well-ordered sets; assume that there is no surjective function mapping a section of $J$ onto $C$. Then there exists a unique function $h: J\to C$ satisfying the equation $$h(x)=\text{smallest}[C-h(S_x)].$$

I do not quite see the relationship between this last theorem to the problem at hand. The theorem implies that if there is no surjection of $A$ onto $B$ then there has to be an injection of $A$ into $B$. But how should I use it on the problem at hand? Thank you very much!

Best Answer

You say:

The theorem implies that if there is no surjection of $A$ onto $B$ then there has to be an injection of $A$ into $B$.

Then if there is no injection $A\to B$, then then there is a surjection $A\to B$ and hence an injection $B\to A$ (AC again). So $\lvert A\rvert\le \lvert B\rvert$ or $\lvert B\rvert\le \lvert A\rvert$.

By the way, the construction to define the function $h\colon J\to C$ actually either yields an order isomorphism from $J$ to an initial segment of $C$ or, if it fails, an order isomorphism from an initial segment of $J$ to $C$. In the latter case, this directly yields an injection from $C$ to $J$.

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