[Math] Does the series $\sum_{n\ge1}\left(-1\right)^n\frac{\cos\left(\alpha n\right)} {\sqrt n}$ converge

calculusconvergence-divergencereal-analysissequences-and-seriestrigonometric series

Does the series $\sum_{n\ge1}\left(-1\right)^n\frac{\cos\left(\alpha n\right)} {\sqrt n}$
converge ?

I tried to deal with this problem this way.
Let $S_k$ be a sequence of partial sums of the given series.

Than
$S_{2k}=\sum_{k=2}^{2n} \frac{\cos\left(\alpha n\right)} {\sqrt n}$,
series $\sum_{k=2}^\infty \frac{\cos\left(\alpha n\right)} {\sqrt n}$ converges by Dirichlet Convergence Test, therefore $S_{2k}$ converges.

And $S_{2k+1}=-\sum_{k=1}^{2n+1} \frac{\cos\left(\alpha n\right)} {\sqrt n}$.

If $S_{2k}\to 0$ than also $S_{2k+1}\to 0$ and the given series converges,
but I do not think that $S_{2k}$ must converge to zero.

Are there another approach to this problem ?

Thanks.

Best Answer

Answer. The series converges iff $a\ne (2k+1)\pi$.

This can be proved using Abel's summation method, since it is a series of the form $$ \sum_{n=1}^\infty a_nb_n $$ with $a_n=\frac{1}{\sqrt{n}}$ decreasing and tending to zero, and $b_n=(-1)^n\cos(an)$ which has bounded partial sums.

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