I can understand the dimension of column space of matrix is the no. of independent column vectors
But why is the dimension of nullspace = no. of free variables?
[Math] Dimension of nullspace
linear algebramatrices
linear algebramatrices
I can understand the dimension of column space of matrix is the no. of independent column vectors
But why is the dimension of nullspace = no. of free variables?
Best Answer
When you find the reduced row echelon form of a matrix, the max number of independent columns (i.e. the column rank) is the number of pivot columns (columns containing a leading one for some row). Notice now that free variables correspond to the columns without pivots. So the number of free variables is $n - \text{column rank}(A)$.
So \begin{align*} \text{nullity}(A) &= n - \text{column rank}(A) \\ &= \text{number of free variables}. \end{align*}