The difference equations below model the yearly populations of wolves and moose, measured in hundreds. The wolves kill the moose for food.
$$\begin{align}
x_n&=x_{n-1}-0.004x_{n-1}+0.002x_{n-1}y_{n-1}\\
y_n&=y_{n-1}+0.005y_{n-1}-0.010x_{n-1}y_{n-1}-0.001y_{n-1}^2
\end{align}$$
I think I've worked out what $x$ and $y$ are correctly.
$x_n$ is predator and $y_n$ is prey. I say this because the $x_n$ has a growth term
$$+ 0.002 x_{n-1}y_{n-1}$$
…which says that $x_n$ grows by interaction between $x$ and $y$. This is classic predation a.k.a. eating prey.
The $y$s have what looks like logistic growth:
$$y_{n-1} – 0.001y^2_{n-1}$$
which says this species has a population growth that is limited by the environment.
However, does anyone know what Matlab commands I would enter to answer this question?
If there are initially $50$ wolves and $300$ moose, use Matlab to obtain plot of $x$ and $y$ versus n on the same graph, for $0 \le n \le 10000$. Remember that $x$ and $y$ are measured in hundreds.
Best Answer
You can simply write it in this way: