This is a pretty basic question about principal ideals – on page 197 of Katznelson's A (Terse) Introduction to Linear Algebra, it says:
Assume that $\mathcal{R}$ has an identity element. For $g\in \mathcal{R}$, the set $I_g = \{ag:a\in\mathcal{R}\}$ is a left ideal in $\mathcal{R}$, and is clearly the smallest (left) ideal that contains $g$.
Ideals of the form $I_g$ are called principal left ideals…
(Note $\mathcal{R}$ is a ring).
Why is the assumption that $\mathcal{R}$ has an identity element important?
Best Answer
Because if $\mathcal{R}$ has an identity, then $I_{g}$ is the smallest left ideal containing $g$. Without an identity, it might be that $g \notin I_{g}$.
For instance if $\mathcal{R} = 2 \mathbf{Z}$, then $I_{2} =\{a \cdot 2:a\in 2 \mathbf{Z} \} = 4 \mathbf{Z}$ does not contain $2$.
(Thanks Cocopuffs for pointing out an earlier mistake.)