[Math] Decimal form of irrational numbers

number theoryprime numberssequences-and-series

In the decimal form of an irrational number like:
$$\pi=3.141592653589\ldots$$
Do we have all the numbers from $0$ to $9$. I verified $\pi$ and all the numbers are there. Is this true in general for irrational numbers ?

In other words, for an irrational number
$$x=\sum_{n\in \mathbb{Z}} a_n 10^n$$

Does $a_n$ takes all the numbers between $0$ and $9$ ?

Best Answer

Certainly not, since rational numbers are exactly the ones with an eventually periodic expansion. So for example, the number $0.01001100011100001111\ldots$ is irrational.

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