I was working on converting an parametric equation into a Cartesian one and i cant seem to figure this one out. I was hoping you could help with that for this equation of a cycloid, Thanks
$x = cos(t)+t+\pi$
$y = cos(t)$
Edit:
Oops
I gave you the wrong equation
$x = sin(t)+t+\pi$
$y = cos(t)$
Sorry About that, And Thanks for the many Answers
Best Answer
If the equations are $$x = \sin(t)+t+\pi\qquad ,\qquad y=\cos(t)$$ you have $$\sin(t)=x-t-\pi$$ $$\cos(t)=y$$ $$\sin^2(t)+\cos^2(t)=(x-t-\pi)^2+y^2=1$$ but $t=\cos^{-1}(y)$. So, in cartesian coordinates $$(x-\cos^{-1}(y)-\pi)^2+y^2=1$$ is the implicit equation.