[Math] Constructing the complex p-adic numbers

p-adic-number-theory

I'm reading through "$p$-adic Numbers, $p$-adic Analysis, and Zeta-Functions" by Koblitz to learn about p-adic numbers. In chapter 3, he describes the construction of $\Omega$ (a.k.a. $\Omega_p$), the completion of the algebraic closure $\overline{\mathbb Q}_p$ of $\mathbb Q_p$. I think this is also called $\mathbb C_p$.

Could one obtain (a field isomorphic to) $\Omega$ more directly by simply completing $\overline{\mathbb Q}$ with respect to the $p$-adic norm $|~~|_p$? The way described in Koblitz starts with $\mathbb Q$ and the norm $|~~|_p$, completes it, constructs the algebraic closure, and then completes it again.

More specifically, the norm $|~~|_p$ should extend from $\mathbb Q$ to $\overline{\mathbb Q}$ in the same way Koblitz describes it extending from $\mathbb Q_p$ to $\overline{\mathbb Q}_p$ (using $\mathbb N_{\mathbb Q(\alpha) / \mathbb Q}$). Then completing $\overline{\mathbb Q}$ with respect to $|~~|_p$ should preserve the property of being algebraically closed using essentially the same proof.

Will this work, or will something go wrong?

Best Answer

This is a community wiki answer based on the comments, plus some remarks of my own.

In principle, yes, you could proceed by extending the $p$-adic valuation from $\mathbb Q$ to $\overline{\mathbb Q}$, and the extending from $\overline{\mathbb Q}$ to $\mathbb C$. But you have to be careful if you want to go this route. In particular, there is not a unique way to extend the $p$-adic valuation from $\mathbb Q$ to $\overline{\mathbb Q}$.

In the comments, it was suggested that perhaps one could define

$$|\alpha|_p := |N_{{\mathbb Q}(\alpha)/{\mathbb Q}}(\alpha)|_p^{1/[{\mathbb Q}(\alpha):{\mathbb Q}]}.$$ So for example, this would give $|1+2i|_5=|1−2i|_5=|5|^{1/2}_5=5^{−1/2}$. However, then we deduce that $$|(1+2i)+(1−2i)|_5 = |2|_5 = 1 > 5^{-1/2} = \max(|1+2i|_5,|1−2i|_5),$$ contradicting the ultrametric inequality.

In general, the number of extensions of $|\cdot|_p$ from $\mathbb Q$ to a finite extension $K$ is equal to the number of prime ideals in ${\cal O}_K$ that lie over $p$. The two extensions of $|\cdot|_5$ to ${\mathbb Q}(i)$ are related to the two primes $1+2i$ and $1−2i$ that divide $5$. For one of the extensions, $|1+2i|=1/5$ (not $1/\sqrt{5}$) and $|1−2i|=1$, while for the other extension $|1−2i|=1/5$ and $|1+2i|=1$.

However, the lack of uniqueness is not a dealbreaker; for every finite extension of $\mathbb Q$ you can pick an extension of $|\cdot|_p$, and use Zorn's lemma to ensure that you're making choices that are consistent with each other.

Once you have an extension to all algebraic numbers, you can extend to transcendental numbers $t$ by the so-called Gauss norm construction: $$ |a_n t^n+\cdots +a_1 t + a_0| := \max_i |a_i|$$ and extending to rational functions of $t$ by multiplicativity.

Although this works, it is generally considered less natural than the standard approach because the extension of the $p$-adic norm from $\mathbb{Q}_p$ to $\overline{\mathbb{Q}}_p$ is unique. This uniqueness is one way in which local fields are simpler than global fields.

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