Assume I have complex number $z = a + ib$.
$z$ can be represented by a polar representation
as $r(\cos \theta+i\sin \theta)$,
when $r$ is the absolute value
of $z$, $\sqrt{a^2 + b^2}$.
But how can I find $\theta$?
complex numberstrigonometry
Assume I have complex number $z = a + ib$.
$z$ can be represented by a polar representation
as $r(\cos \theta+i\sin \theta)$,
when $r$ is the absolute value
of $z$, $\sqrt{a^2 + b^2}$.
But how can I find $\theta$?
Best Answer
Consider the following Argand-diagram
The y-axis is the imaginary axis and the x-axis is the real one. The complex number in question is
$$x + yi$$
To figure out $\theta$, consider the right-triangle formed by the two-coordinates on the plane (illustrated in red). Let $\theta$ be the angle formed with the real axis.
$$\tan\theta = \frac{y}{x}$$
$$\implies \boxed{\tan^{-1}\left(\frac{y}{x}\right)}$$
The hypotenuse of the triangle will be
$$\sqrt{x^2 + y^2}$$
Therefore,
$$\sin\theta = \frac{y}{\sqrt{x^2 + y^2}}$$