I'm trying to prove the following (well-known) theorem in symplectic geometry.
Theorem . For $(M, \omega)$ a symplectic manifold with Riemannian metric $g, \exists$ a canonical almost complex structure $J$ compatible with $ω$.
(source)
Could someone give me a sketch and I can fill in the details. Thank you.
Best Answer
This is well-explained in a number of standard references such as da Silva or McDuff-Salamon's Introduction to Symplectic Topology. I'll tour the exposition in da Silva (ch. 12).
We start with some basic symplectic linear algebra. Let $V$ be a vector space with nondegenerate symplectic form $\Omega$ and Riemannian form $G$.
There is a unique linear map $A: V \to V$ such that $\Omega(u,v) = G(Au,v)$ for all $u, v \in V$. (Use nondegeneracy.)
Let $A^*$ be the adjoint of $A$. The map $AA^*$ is symmetric and positive-definite. (Use the Riemannian property.)
Hence $AA^*$ diagonalizes with positive eigenvalues by the spectral theorem, and thus has a square root (defined eigenspace-by-eigenspace).
You can think about the above as being a pointwise version of the result you want. Recall that an almost complex structure on a manifold is a smoothly varying family of complex structures on the tangent spaces, so all you have to do is check that $J$ depends smoothly on $G$ and $\Omega$ (this is not complicated - if you are working hard something is going wrong).
All this is "canonical" in a certain sense because we've made no choices along the way. $A$ is unique and depends only on the maps $G$ and $\Omega$, and $J$ depends only on $A$. We've made no reference to bases anywhere.