I have an irregular hexagon that is $1\,mm$ thick. The total area of the hexagon is $114.335\,cm^2$.
How do I calculate the volume?
[Math] Calculating volume by area and thickness
volume
Related Solutions
The solution in the polar coordinates system where the lemniscate is given by the formula $r^{2}=2a^{2}\cos2\phi$.
Surface area can be obtained by using the formula $A=2\pi\int_a^br(\phi)\sin\phi\sqrt{r^{2}(\phi)+[dr(\phi)/d\phi]^{2}}d\phi$: $$A=2\pi a^{2}\sqrt{a}\int_a^b\sin\phi\sqrt{\cos2\phi +sin^{2}2\phi } d\phi$$ The integral above seems to have no analytical solutions.
The formula for the volume is pretty simple and can be obtained directly from the formula $V=\pi\int_a^b r^2(\phi)d\phi$ : $$V=2a^{2}\pi\int_a^b cos2\phi d\phi$$
We need to find the area of top and bottom surfaces.
You can also visit: http://mathworld.wolfram.com/PyramidalFrustum.html
Best Answer
Volume is in general Area times Depth. Just by knowing the area and thickness, you can multiply these together. Make sure you first convert your units to either mm or cm. 1mm = .1cm Your answer would then give you cm^3 (centimetres cubed) as units