[Math] Calculating time of flight of object (Mechanics – horizontal elevated launch)

classical-mechanicsmathematical modeling

I need help with the following question:

A smooth spherical object is projected horizontally from a point of vertical height H = 25.78 metres above horizontal ground with a launch speed of u = 24.23m/s . Calculate the time of flight of the object, in seconds, from its point of launch till it hits the ground. Assume that air resistance is negligible and take g = 9.81.

Appreciate any comments and feedback on this. Thanks.

Best Answer

Hints:

  1. You can ignore the horizontal velocity as it is constant and with no air resistance does not affect the answer
  2. So in effect you can take the object as being dropped with initial vertical velocity $0$
  3. You may have a formula which allows you to find the time at which it travels a given distance with constant acceleration.
  4. If not, then see that the speed downwards at time $t$ is $v=v_0+gt$ where $v_0=0$. You can integrate this to find the distance travelled as a function of time, and then solve to find the time at which the distance is $H$.
  5. You teacher may prefer you to do this the other way round, so you would be looking at negative speeds upwards with $v=v_0-gt$, and start at a distance $H$ and end at a distance $0$.
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