Hi I am new to the board. Taking a computer architecture course and I am having trouble understanding further simplification on a question I got on a previous quiz. When I type in the expression after setting up my K map and simplifying I come to this:
(A AND B) OR (NOT A AND NOT B).
Through the rules of simplification A+ NOT A=1. Does this then mean that AB +A'B'=1? and if so how is that represented as a logic gate?
Thanks.
Best Answer
Let's have the truth table of
AB + A'B'
.The assertion that
AB + A'B' =1
is definitely not true. Now the source of confusion seems to be the following.If
A + A' = 1
then shouldAB + A'B'
is also equal to 1. NO. The complement of AB is(AB)'
and notA'B'
.Use de-Morgan theorem on
(AB)'
and you get the following,BOOLEAN GATES REPRESENTING (AB)'