Independent Bernoulli trials are performed, with probability $1/2$ of success, until there has been at least one success. Find the PMF of the number of trials performed.
How is this different from the negative binomial?
probability distributions
Independent Bernoulli trials are performed, with probability $1/2$ of success, until there has been at least one success. Find the PMF of the number of trials performed.
How is this different from the negative binomial?
Best Answer
This is the geometric distribution, # of trials needed to get first success
$P(x=k) = (1-p)^{k-1}\cdot p$
The negative binomial distribution gives the # of trials needed to get k successes
So, as has been commented, the geometric distribution is a special case of the negative binomial distribution.
Note
Some count the # of failures for the negative binomial, but as you must be knowing, what is defined as "success" is just a matter of convenience.