[Math] Area under a curve of an odd function from negative infinity to positive infinity

even-and-odd-functionsimproper-integralsintegration

In integration, there is a property that says: If you're integrating from -a to a some odd function f(x), then the area under the curve between -a and a is zero.

I was listening to this in class , and then I thought about integrating some odd function, like x^3, from negative infinity to positive infinity.

But, if you integrate x^3 and then solve it from negative infinity to positive infinity, wouldn't you end up subtracting infinity from infinity, which is undefined?

Given this, which answer is the correct one: is the area 0 or is it undefined?

Best Answer

For improper integrals, you're correct: you have to be careful. Both limits need to exist independently of each other. In your case, $\int_{-\infty}^0 x^3\,dx$ is $-\infty$, hence the integral "doesn't exist" (except in the extended real numbers case). There is something called a principal value, where you take the limits simultaneously, e.g., $$\lim_{N\to\infty}\int_{-N}^N x^3\,dx=\lim_{N\to\infty}0=0,$$ and in this sense, the limit will always give $0$.