Geometry – Area of a Square Inside a Square Created by Connecting Point-Opposite Midpoint

Question

Square $ABCD$ has area $1cm^2$ and sides of $1cm$ each.

$H, F, E, G$ are the midpoints of sides $AD, DC, CB, BA$ respectively.

What will the area of the square formed in the middle be?

I know that this problem can be solved by trigonometry by using Area of triangle ($\frac{1}{2}ab\sin{c}$) but,
is there another method or visual proof?

Answer 1

By moving small triangles we can make $5$ equal small squares.