[Math] Area of a Parallelogram Using Vectors

Question

I am not sure if I am doing this problem correctly. I need to find the area of the parallelogram whose vertices are the points $P(0,1,1), Q(1,2,1), R(2,4,1), S(3,5,1)$

So to find the area I need to calculate the magnitude of the cross product of the vectors, that is $||\vec{A}X\vec{B}||$, correct?

Then I can pick any 3 points to find vectors $\vec{A}$ and $\vec{B}$

$\vec{A}=\overrightarrow{PQ}=<1-0,2-1,1-1>$ and $\vec{B}=\overrightarrow{PR}
=<2-0,4-1,1-1>$

I get $||\vec{A}X\vec{B}||=1$ after computing the cross product, is this correct?

Answer 1

Your answer is correct.