Any feasible solution of a linear programming problem can be expressed as the convex combination of Basic Feasible Solutions of the same.
Is the statement true?
I think the statement is true. Can anyone please help me to understand why this statement is true if it is true?
Best Answer
Consider the following problem.
$\min 0$ subject to $x \in \mathbb{R}$.
It has no basic feasible solution. The statement is false.
Edit:
Consider $\max y$ subject to $ x \ge 0, y \ge 0$.
The only basic feasible solution is the zero vector.
Note that a feasible region can be unbounded but the convex combination of BFS must be bounded. The statement is false unless the linear program has a bounded feasible region.