[Math] An elegant way to solve $\frac {\sqrt3 – 1}{\sin x} + \frac {\sqrt3 + 1}{\cos x} = 4\sqrt2 $

algebra-precalculustrigonometry

The question is to find $x\in\left(0,\frac{\pi}{2}\right)$:

$$\frac {\sqrt3 – 1}{\sin x} + \frac {\sqrt3 + 1}{\cos x} = 4\sqrt2 $$

What I did was to take the $\cos x$ fraction to the right and try to simplify ;

But it looked very messy and trying to write $\sin x$ in terms of $\cos x$ didn't help.

Is there a more simple (elegant) way to do this.

Best Answer

$\sin(\frac{\pi}{12}) = \frac{\sqrt{3}-1}{2\sqrt{2}}$ and $\cos(\frac{\pi}{12}) = \frac{\sqrt{3}+1}{2\sqrt{2}}$. Plugging them into your equation yields $\sin(x+\frac{\pi}{12}) = \sin(2x)$. So $x = \frac{\pi}{12}$

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