[Math] adjoint representation is irreducible iff $\mathfrak{g}$ is simple

lie-algebraslie-groupsrepresentation-theory

I am trying to prove that for a Lie algebra $\mathfrak{g}$:

$ad_{\mathfrak{g}}$ the adjoint representation of $\mathfrak{g}$ is irreducible iff $\mathfrak{g}$ is simple.

I tried to use the fact that stable ideals of $ad_{\mathfrak{g}}$ are ideals of $\mathfrak{g}$: Then if $\mathfrak{h}$ is a stable space under $\mathfrak{g}$ it is $\{0\}$ or the entire $\mathfrak{g}$. but I Couldn't go further.

Thank you for your help.

Best Answer

Subrepresentations of the adjoint representation just correspond to ideals of $\mathfrak{g}$. Since $\mathfrak{g}$ is simple, they are trivial or the whole Lie algebra. Hence the adjoint representation is irreducible.

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