There is a 10 floors building, 10 people get in the elevator in the ground floor and get off at each floor independently. What is the probability that the elevator stops at floor 5?
My answer is that because there are 10 floors so the probability that the elevator stops at floor 5 (same as floor 1,2,3,4..) is 1 – (9/10)
Is my answer correct here? I think it's too simple for this question.
Best Answer
The way I view this, there are $10$ floors, each person getting into an elevator has a probability of getting off on the 5th floor of $1/10$ and not getting off there of $9/10$. The probability of all $10%$ people not getting off on the 5th floor is $(9/10)^{10}$; therefore, the probability that the elevator stops on the fifth floor at all is the probability that at least one person gets off on the 5th floor, or
$$1-\left ( \frac{9}{10}\right)^{10} \approx 0.6513$$