[Math] A line integral involving $\log \zeta(s)$

complex-analysisnumber theoryriemann-hypothesisriemann-zeta

Let $\zeta$ denote the Riemann zeta function. Using the Cauchy integral theorem, can you evaluate

$$I=\int_{\Re(s)=\frac{1}{2}} \frac{(2s-1)}{s^{2}(1-s)^2}\Bigg[\int \log((s-1) \zeta(s)) \mathrm{d}s\Bigg] \mathrm{d}s?$$

Note that $I$ converges since $\zeta(s)=O(|s|)$.

I have provided an answer below as an attempt.

Best Answer

One trivial mistake that blows your argument away is that RZ is infinity at 1 so its log is not defined in your S; you need S to exclude the real line, so you have to work for t>T>0 as otherwise, you cannot apply the residue theorem since you would have a logarithmic singularity at 1

(edited later after tons of corrections by the original poster to address various objections for careless flaws that appeared in the original computation):

The main flaw of the computation lies in the misunderstanding of the complex-log, namely that while the complex-log behaves on branch points as noted in the paper by Bui et al referred in the comments from which the original poster copy pasted his argument - so it jumps by 2*Pii when crossing such-, its primitive doesn't as shown by the simple example of log(z) vs zlog(z)-z on the complex plane minus the negative axis.