My Calculations:
$$\frac{4}{6}\times\frac{3}{5}\times\frac{2}{4}\times\frac{1}{3} = \frac 1 {15}$$
Is that correct?
[Math] $4$ women and $2$ men are being interviewed. Find the probability the women will be interviewed first.
algebra-precalculuscombinatoricsstatistics
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Best Answer
Yes, the result is correct. And a more direct reasoning might be the following:
There're 6! permutations (orders) of the interviews, and 4!2! of them satisfy your limit that all four women come first. So $P=\frac{4!2!}{6!}=\frac{1}{15}$.