Let $(X_n)_{n\geq1}$ be a sequence of random variables such that
$$ \mathbb{P}(X_n= n^{2/3})=1-\mathbb{P}(X_n=0)=\frac{1}{3n}$$
Find $\lim\sup X_n$ and $\lim\inf X_n$.
We know that
\begin{align}
\{\omega:\limsup X_n(\omega) = +\infty\}
\end{align}
is equivalent to
\begin{align}
\forall A >0, \exists n_0\in\mathbb{N} \quad&\text{s.t}\quad \forall n\geq n_0, \quad\sup_{k\geq n}X_k >A \\
\forall A >0, \exists n_0\in\mathbb{N} \quad&\text{s.t}\quad \forall n\geq n_0, \;\exists k\geq n, \quad X_k >A
\end{align}
and thus we have that
\begin{align}
\{\omega:\limsup X_n(\omega) = +\infty\} = \bigcap_{A>0}\lim\sup\{X_k>A\}
\end{align}
and we actually take a sequence $A_k$ of rationals such that $A_k \uparrow \infty$ to make sure that the event is measurable. Finally we check that, $\forall A_k>0$,
$$
\sum_{n\geq 1}\mathbb{P}(X_n > A_k) = \sum_{n\geq A^{3/2}}\mathbb{P}(X_n = n^{2/3}) = \sum_{n\geq A^{3/2}}\frac{1}{3n}
$$
which diverges because it's basically the harmonic series less a finite set of terms and multiplied by a constant and we conclude by the second Borel-Cantelli lemma that the event occur almost-surely and as all the events of the intersection happen almost-surely then
$$
\mathbb{P}\left(\bigcap_{A_k>0}\lim_n\sup\{X_n>A_k\}\right)=1
$$
The $\lim\inf X_n =0$ goes about the same way as I found in other posts, however I don't know if the above answer I wrote is correct. I found many questions showing the calculations for the case where limit superior and limit inferior are equal to a constant, but didn't find any about the sequence diverging.
Best Answer
Let $B_n$ be the event $\{X_n=n^{2/3}\}$. Then $\sum_{n\geqslant 1}\mathbb P(B_n)$ diverges hence, as you noticed, by the second Borel-Cantelli lemma, $\limsup_{n\to \infty}B_n$ has probability one hence for almost every $\omega$, there exists an infinite set $I(\omega)\subset\mathbb N$ such that for each $n\in I(\omega)$, $\omega\in B_n$ (that is, $X_n(\omega)=n^{2/3}$) hence we reach your conclusion in a bit shorter way.