Justification of the tangent name for the goniometric operator $\tan$

algebra-precalculusdefinitiontrigonometry

When we give a proof that the tangent is the sine to cosine ratio of an oriented angle,

$$\bbox[5px,border:2px solid #C0A000]{\tan \alpha=\frac{\sin\alpha}{\cos \alpha}}$$
with $\cos \alpha \neq 0$, we take the tangent $t$ in $A(1,0)\equiv S$ to the circle of center in $O(0,0)$ ad radius $r=1$. See the image

https://www.youmath.it/images/stories/funzioni-elementari/definizione-tangente.png

The name tangent has been given because we consider the tangent to the circle of radius $1$ at point $A\equiv S$ or for another reason?

Best Answer

This is a good reason and it is consistent also with the other equivalent definition for the tangent

enter image description here

(credit)

Refer also to The Etymology of Trig Functions.