Issue with distance point-to-line

geometry

I am having a small issue with the distance calculation of a point-to-line and I cannot find the mistake.

I have the line:

$$x + 2y + 3 = 0$$

And I am trying to compute its distance to point $(x_0, y_0) = (0,0)$. According to the well-known formula:

$$ d = \frac{\left|ax_0+by_0+c\right|}{\sqrt{a^2 + b^2}} = \frac{\left|3\right|}{\sqrt{5}} = 1.3416$$

Now, I try to compute the same distance on a different manner. The line intersects the $y$ axes at $p=(0, -1.5)$. I am trying to solve the following triangle (sorry for the cheap plotting):

Triangle to solve

The distance computed before should correspond to the length of the red segment (perpendicular to the line that goes through the desired point), which could also be computed as:
$$ d = 1.5 \cdot cos(30^{\circ}) = 1.299$$

Both results for the length of the red segment do not match. What am I doing wrong?

Thank you in advance!

Best Answer

The angles are wrong - instead of $30^0$ it should be $\arctan(0.5) = 26.56^0$