Is the derivative of the elliptic integral of the first kind considered a mathematical discovery

calculuselliptic integralssoft-questionspecial functions

I am new to elliptic integrals and did not learn about them in a formal setting (I learned about them from Wikipedia and my own fiddling). I recently attempted to take the derivative of the complete elliptic integral of the first kind with respect to $k^2$ such that I was performing $$\frac{\partial K(\phi)}{\partial \phi} = \frac{\partial}{\partial \phi} \int_0^\frac{\pi}{2}\frac{d\theta}{\sqrt{1 – \phi \sin^2\theta}}$$ where $\phi = k^2$. In so doing, I arrived at the very same road block asked about in this question. The answer to this question gives a proof that the derivative can be expressed in terms of elliptic integrals of the first and second kind (which is amazing to me and I consider quite lucky). The approach of the proof was surprising and seemed to come out of nowhere. I consider myself a moderately skilled mathematician and I would never have been able to come up with such a solution, especially due to the fact that, while those integrals in the question are in fact equal, their integrands are not.

My question is very simple. Is this derivative considered a mathematical discovery that took considerable time and thought, or is it considered to be obvious? Should I feel bad that this was nowhere near obvious to me?

P.S. I was able to evaluate the integral above using the result of $\frac{\partial K(k)}{\partial k}$ from the referenced question and the fact that $$\frac{\partial K(k)}{\partial k}\Bigg\rvert_{k = \sqrt{\phi}} = \frac{\partial K(\phi)}{\partial \phi}\frac{\partial \phi}{\partial k}\Bigg\rvert_{k = \sqrt{\phi}}$$ thus $$\frac{\partial K(\phi)}{\partial \phi} = \frac{1}{2\phi}\left(\frac{E(\phi)}{1 – \phi} – K(\phi)\right)$$

Best Answer

The specific result you asked about $$ \frac{\partial K(k)}{\partial k} = \frac{1}{2\phi}\left(\frac{E(\phi)}{1 - \phi} - K(\phi)\right) $$ is essentially DLMF equation 9.4.1 $$ \frac{\partial K(k)}{\partial k} = \frac{E(k) -k'^2 K(k)}{k\,k'^2} $$ which also appears in the Wikipedia article Elliptic integral.

The development of elliptic integrals started in the $17$th century with contributions by Landen, Fagnano and Euler. It continued into the $18$th century and extended to elliptic functions with contributions by Legendre, Gauss, Abel, Jacobi and many others. This specific result I don't consider obvious. As usual in this case, just as for integrals, it is a lot easier to check if it is correct once you have the right answer but hard to come up with the answer in the first place.