Is a local ring Artinian, if the maximal ideal is nilpotent

abstract-algebraartiniancommutative-algebra

This answer suggests the idea, that a local ring $(R, \mathfrak{m})$ whose maximal ideal is nilpotent is in fact an Artinian ring.

Is this true? If so, how is it proven?

Best Answer

You need that $R$ is noetherian, else there are counterexamples.

E.g., take $R = K[x_i]_{i \in \mathbb{N}}/(x_i | i \in \mathbb{N})^2$.

If $R$ is Noetherian, this is a special case of Lemma 10.59.4 here which states that a Noetherian ring of dimension $0$ is Artinian.

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