In an ultrametric space, is every open set closed

general-topologymetric-spaces

I saw the following well-known fact for ultrametric spaces

Every open ball is closed.

So this stimulates me to think whether this is true for open set or not.

By an ultramtric space, it's a metric space $(M,d)$ whose metric satisfies the following condition (stronger than triangle inequality):
$$
d(x,z) \leqslant \max \{ d(x,y), d(y,z)\}, \;\; \forall \; x,y,z \in M.
$$

My attempt:

After I try to prove this statement is true by contradiction argument, I realized there is always a gap. So I believe this is false now. But I can't still find a counterexample.

I also try to google some key words, but things I can find out are for open balls. I don't see any discussion for my problem.

Best Answer

No. In the $p$-adic numbers $\Bbb Q_p$, one-point subsets such as $\{0\}$ are closed, but not open. The complement of a one-point subset is open, but not closed.

Related Question