If $u_n= \int_1^ne^{-t^2}dt$, what can be said about $\sum u_n$

real-analysissequences-and-series

If

$\displaystyle u_n= \int_1^ne^{-t^2}dt$ where $n=1,2,3…$

Then Which of the following is true

$1)$ both the sequence $u_n$ and series $\sum u_n$ is convergent

$2)$ both the sequence $u_n$ and series $\sum u_n$ is divergent

$3)$ The sequence is convergent and $\sum u_n$ is divergent

$4)$ $\displaystyle \lim_{n \to \infty}u_n=\frac{2}{e}$

The solution I tried – I know that $\displaystyle\int_0^{\infty} e^{-t^2}=\sqrt \pi$ ,but how to calculate the $u_2,u_3…$ I have no idea please help

Best Answer

The sequence $u_n$ is convergent to $C=\int_{1}^{+\infty}e^{-t^2}\,dt$. Because of this, the series $\sum u_n$ is divergent.

No quantitative estimation is really needed, but if you want one

$$ u_n = C-\int_{n}^{+\infty}e^{-t^2}\,dt = C-\frac{1}{2}\int_{n^2}^{+\infty}\frac{dt}{e^t\sqrt{t}}\geq C-\frac{1}{2n}\int_{n^2}^{+\infty}\frac{dt}{e^t}=C-\frac{1}{2ne^{n^2}}. $$

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