I have the following problem to simplify and I am lost on how to proceed:
$\frac{\sqrt{1-x}+3}{2}$
I'm aware that I can rewrite $\sqrt{1-x}$ as $(1-x)^\frac{1}{2}$ but then I don't know where to go from there.
The solution provided is $\sqrt{\frac{1}{x}+2}$.
How can I arrive at this solution? More granular baby steps very much appreciated.
Best Answer
These two expressions are not equal.
\begin{array}{c|cc} x & \frac{\sqrt{1-x}+3}{2} & \sqrt{\frac{1}{x} + 2} \\ \hline 2 & \text{undefined} & \sqrt{\frac{5}{2}} \\ 1 & \frac{3}{2} & \sqrt{3} \\ 0 & 2 & \text{undefined} \end{array}