Hilbert space sum

functional-analysishilbert-spacesreal-analysis

Let $\{x_i\}_{i\in I}$ as orthonormal set in Hilbert space,

Now define $x = \sum_{i\in I}a_ix_i$ , can we prove $a_i = (x,x_i)$? If $I$ is uncountable set?

I know if we further impose $\sum_{i\in I}|a_i|^2 <\infty$ then set of $i$ such that $a_i \ne 0$ is almost countable(then taking limit,due to continuous of inner product),what about the case without this assumption?

Best Answer

It depends on your definition of "$x = \sum_{i \in I} a_i \, x_i$". I would say that for any reasonable definition, this series converges if and only if $\sum_{i \in I} |a_i|^2 < \infty$.

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