I have a question about the notation for "$n$-handles" with respect to a decomposion of handlebodies.
At german wikipedia page https://de.wikipedia.org/wiki/Henkel-Zerlegung
I found a statement that every closed orientable $2$-manifold has following handle decomposion:
-one $0$-handle (so a punctured $2$-sphere)
–$2g$ $1$-handles (cylinders) where $g$ is the genus of the surface
-one $2$-handle
Could anybody explain/ visualize to me this decomposion?
Best Answer
When constructing an $n$-manifold, a $j$-handle is an $B^{j} \times B^{n-j}$, where $B^{k}$ is a $k$-ball and is attached to the rest of the manifold along $S^{j-1} \times B^{n-j}$, where $S^k$ is a $k$-sphere.
Since you are making a $2$-manifold,
This image (from "Efficient Edgebreaker for surfaces of arbitrary topology" by Lewiner, Lopes, Rossignac, Vieira) starts with a $0$-handle in the upper-left, attaches a $1$-handle, then another, and finally fills in the "gap" between the unglued sides of the $1$-handles with a $2$-handle. (Montesinos, Classical Tesselations and Three-Manifolds, discusses this, with diagrams, in section 1.2.)
An equivalent way to specify a $2$-manifold is by identifications of a disk. Examples. The equivalence of these two descriptions is fairly straightforward.
Let $M$ be the oriented, closed, genus $g$ $2$-manifold. It has a specification by a polygon with $2g$ edges. To specify the labels and orientations, we pick an orientation for the $2$-cell filling the polygon, which induces an orientation on the boundary (either clockwise or anticlockwise). Then we indicate by a superscript on the label whether the edge is oriented in the same direction ("$1$") or in the opposite direction ("$-1$"). Then a labelling of the polygon with identifications producing $M$ is $a_1 b_1 a_1^{-1} b_1^{-1} a_2 b_2 a_2^{-1} b_2^{-1} \dots a_g b_g a_g^{-1} b_g^{-1}$. As a handle decomposition: