I can't seem to figure out this problem.
The point P(1,0) lies on the curve $y=\sin(10\pi/x)$.
If Q is the point $(x,\sin(\frac{10\pi}{x}))$, find the slope of the secant line PQ (correct to four decimal places) for x = 2.
I have tried doing the slope formula $\frac{y_1-y_2}{x_1-x_2}$.
since $\sin(\frac{10\pi}{2}) = 0.2707$ I think that, when $x = 2$, $Q = (2,0.2707)$.
since $P = (1, 0)$, the slope formula becomes, $\frac{.2707 – 0}{2 – 1} = 0.2707$
But this answer is wrong. How can I get the right answer?
Best Answer
$$\sin\frac{10\pi}2=\sin5\pi=\sin\pi=0$$ I assume that you used degrees instead of radians to calculate the sine.