An investigator interested in estimating a population mean wants to be 95% certain
that the length of the confidence interval does not exceed 4. Find the required
sample size for his study if the population standard deviation is 14.
My work:
Confidence interval: $95$%
Error estimate(E): $4$
$\sigma=14$
$\alpha=0.05$ so $\alpha/2=0.025$
$Z_{0.025}=1.96$
so using $n =(\cfrac{Z_{0.025} \cdot \sigma}{E})^2 = (\cfrac{1.96 \cdot 14}{4})^2 = 47.0596$
The sample size cannot be a decimal so round up to $48$ so $n = 48$
So he needs a sample size of $48$ but the book's answer says it's $n = 189$
I have no idea how this is right. Please help me.
Best Answer
When the length of the confidence interval is 4, the value of E is 2.