Problem:
I'm asked to find the length of $m$, given the following diagram.
Note that $\overline{AC}$ = 1 and $\overline{CD} = 1$ and that $\overline{AB}$ is a diameter whose length is 4.
Attempt:
I know that $\angle ADB$ is a right angle and that if I can find the length $\overline{AD}$ then this will be solved. I also know that $\triangle AGE \sim \triangle ADB$. And I now that the measure of $\angle ABD$ is half the measure of angle $\angle AED$ (one segment of which is not shown).
Question:
How can I go about finding the lengths of $\overline{AG}$ or $\overline{AD}$?
Best Answer
We know the following:
We will use the Pythagorean Theorem and the following relationships to find $k$:
Based on the relationships above, we can form a system of equations to find the value of $k$:
\begin{align*} (2-t)^2 + q ^2 &= 1 && \text{substitution}\\ q^2 &= 1- (2-t)^2 \\ q &= \sqrt{1-(2-t)^2} \\ (\sqrt{1-(2-t)})^2 + t^2 &= 2^2 && \text{substitution}\\ -t^2 +4t -3 + t^2 = 4 \\ 4t-3 &= 4 \\ t &= \frac{7}{4} \\ 2(\tfrac{7}{4}) &= k && \text{substitution}\\ k &= \frac{14}{4} \\ k &= 3.5 \end{align*}
Thus, the measure of $k$ is $3.5$ units.