Factoring out a greatest common factor from an expression raised to a power.

algebra-precalculusfactoring

I noticed that it's possible to factor out the greatest factor from an expression raised to power without having to resolve the power first.

For example,

$(3x^4 +15x^2)^2 = (3x^2)^2\cdot(x^2+5)^2 = 9x^8+90x^6+225x^4$

Which is equivalent to having resolved the power first

$(3x^4 + 15x^2)^2 =(3x^4 + 15x^2) \cdot (3x^4 + 15x^2) = 9x^8+90x^6+225x^4$

In general, it seems that

$(ca + cb)^n = c^n (a+b)^n$

Where $a, b, c$ are monomials and $n$ is a constant

Also, it would seem that if we have two factors both raised to the same power then we can distribute.

$c^n (a+b)^n = (ca + cb)^n$

Where $a, b, c$ are monomials and $n$ is a constant

I'm wondering why this appears to be true as in what properties does this observation follow from?

Best Answer

This is rule 2 as explained here:

http://www.mclph.umn.edu/mathrefresh/exponents2.html

This is just rearranging the terms being multiplied in a product. For example:

$$(ab)^3 = (ab)*(ab)*(ab)$$

I can rearrange the a's and b's to bring the a's together and b's together. This follows from the associative and commutative properties of multiplication.

$$(ab)*(ab)*(ab) = (a*a*a)*(b*b*b) = a^3b^3$$

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