Every first contable locally convex space has a countable neighborhood basis of balanced and convex sets

general-topologylocally-convex-spacestopological-vector-spaces

Terminology: By a neighborhood of a point $x$ on a topological space, I mean any subset $V$ which contains an open set containing $x$. A set $B$ in a vector space $X$ is called balanced if $\lambda B \subseteq B$ for every $|\lambda| \le 1$.

Let $X$ be locally convex and suppose it is first countable. In particular, $X$ has a countable neighborhood basis of the origin. Because $X$ is locally convex, we know that (a) every element of such basis is balanced and (b) $X$ has a neighborhood basis of the origin consisting of balanced and convex sets.

Question: How can we find a countable neighborhood basis of the origin consisting of balanced and convex sets?

Best Answer

Let $(U_n)_n$ be any countable local base at $0$ for $X$.

As you stated under (b), for each $n$ we can find a convex balanced neighbourhood $V_n$ of $0$ such that $V_n \subseteq U_n$, as $X$ is locally convex.

It’s immediate that $(V_n)_n$ is your required local countable base at $0$.

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