$$\int_0^\infty\dfrac{x}{\sqrt{x^5+1}}dx$$
I tried out few things, but none helped at all. Is it possible to evaluate the integral using Euler's substitutions (as demanded by my professor)? Also is there any other elementary way of solving it?
definite integralsintegration
$$\int_0^\infty\dfrac{x}{\sqrt{x^5+1}}dx$$
I tried out few things, but none helped at all. Is it possible to evaluate the integral using Euler's substitutions (as demanded by my professor)? Also is there any other elementary way of solving it?
Best Answer
Hint:
$$B(x,y)=\int_0^{\infty}\frac{t^{x-1}}{(1+t)^{x+y}}dt$$
Where $B(x,y)$ is the Standard Beta function and $\displaystyle B(x,y)=\frac{\Gamma(x)\Gamma(y)}{\Gamma(x+y)}$ where $\Gamma(z)$ is the Complete Gamma function.
In your given question, what happens if you substitute $\displaystyle x=t^{\frac{1}{5}}$?