Evaluate $\displaystyle\sum_{k=1}^n \left(\frac{{n-1 \choose k-1}}{k}\right)$

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Evaluate : $\displaystyle\sum_{k=1}^n \left(\frac{{n-1 \choose k-1}}{k}\right)$

Alright so I'm completely stumped, I've never evaluated a summation of $\displaystyle{n \choose k}$.

My best guess is to use the binomial theorem, but I don't know how to change this into a form I could use the theorem on.

A little guidance please?

Best Answer

Hint:

Use the recurrence relation $$\binom nk=\frac nk\binom{n-1}{k-1}$$ and remember that $\displaystyle\sum_{k=0}^n\binom nk=\cdots$