Eigenvectors and eigenvalues of a permutation matrix

Question

I am calculating the eigenvalues and eigenvectors of a permutation matrix:
$$
\mathbf{C}=\left[\begin{array}{ccccc}
0 & 0 & \cdots & 0 & 1 \\
1 & 0 & \cdots & 0 & 0 \\
0 & 1 & \ddots & 0 & 0 \\
\vdots & \vdots & \ddots & \ddots & \vdots \\
0 & 0 & \cdots & 1 & 0
\end{array}\right]_{N \times N}
$$

I noticed that $C^N = I$, where $I$ is an identity matrix.

Supposing the eigenvalues of $C$ is $\mathbf{\lambda}$, I got $\lambda_k = e^{-jk\frac{2\pi}{N}}$.

Now I wonder how to calculate the eigenvectors of this matrix.

Thank you for your helping~

Answer 1

Outline

Simply use the definition of eigenvectors. Suppose $v=\begin{bmatrix}v_1\\v_2\\\vdots\\v_N\end{bmatrix}$ is the eigenvector of this matrix for the eigenvalue $\lambda_k=\exp(-jk2\pi/N)$. Hence $$ Cv=\lambda_kv\implies \begin{bmatrix}v_N\\v_1\\v_2\\\vdots\\v_{N-1}\end{bmatrix} =\begin{bmatrix}\lambda_kv_1\\\lambda_kv_2\\\lambda_kv_3\\\vdots\\\lambda_kv_{N}\end{bmatrix} $$ and solve by recursive substitution.