So I have the following question:
You have a triangle with one angle that is $135°$. The opposite side is $2 *\sqrt{{10}}$ and the adjacent side is $2 *\sqrt{{2}}$.
I used Pythagoras equation and got $4 *\sqrt{{3}}$
My problem is I dont know how I would draw my triangle with the exact angles and sides measurement that is given.
Best Answer
Let $\Delta ABC$ be our triangle, $\measuredangle ABC=135^{\circ},$ $BC=2\sqrt2$, $AC=2\sqrt{10}$
and let $CD$ be an altitude of $\Delta ABC.$
Thus, $BD=CD=2$ and we can draw $\Delta ACD$ and from here we can draw $\Delta ABC.$