Determinant of a $3\times 3$ real symmetric matrix

determinantmatricespositive-semidefinitesymmetric matrices

Let $A$ be a real symmetric $3\times 3$ matrix with entries belonging to the set of non-negative integers. Also assume that each diagonal entries are greater than or equal to all the entries in the row and column in which the diagonal entry belongs.

I want to know whether all the eigenvalues of the matrix is non-negative, i.e., it is a positive semidefinite matrix or not.

Note that this is true if we consider the $2\times 2$ matrices of the above type. I just want to know whether this is true for $3\times 3$ case.

Best Answer

It's not true. The following matrix, for example, has a negative determinant (and therefore a negative eigenvalue). $$\begin{bmatrix}1&1&0\\ 1&2&2\\ 0&2&2\end{bmatrix}$$

Its determinant is $-2$.

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