I tried to solve the following question, but I get the feeling I am doing a few things wrong, but cannot really find out what.
So the exercise is:
Let $\alpha, \beta \in \Omega^{1}(M)$ for a manifold $M$. And let a connection (''locally'') be given by $\nabla = d + A$ where $A$ is the following matrix: $$ \begin{pmatrix} 0 & \alpha \\ 0 & \beta \end{pmatrix} .$$
Compute the curvature of the connection over the trivial rank 2 vector bundle over M, and state conditions for this connection to be flat.
I've got as far as simply using the definition of curvature (and flatness) given: $\kappa_\nabla = dA + A \wedge A = 0$ to find:
$$ \kappa_\nabla = \begin{pmatrix} 0 & d\alpha \\ 0 & d\beta \end{pmatrix} + \begin{pmatrix} 0 & \alpha \wedge \beta \\ 0 & 0 \end{pmatrix} .$$
Then I'd say the conditions are: $d\alpha + \alpha \wedge \beta =0$ and $d\beta = 0$. A section $s$ of the trivial vector bundle of rank 2 is nothing else than an element $s \in C^{\infty}(M)^{\oplus2}$ so $s:= (f_1,f_2)$. We see then that:
$$ \kappa_\nabla(s) = \begin{pmatrix}f_1 d\alpha \\ f_2 d\beta \end{pmatrix} + \begin{pmatrix} f_1 \alpha \wedge \beta \\ 0 \end{pmatrix} .$$
I feel like I've gone wrong because:
- I haven't used the fact that this is the trivial rank 2 vector bundle over M. Perhaps only in implicitly assuming the local expression of $d+A$ is valid everywhere.
- This feels like too little work, can the conditions for example be worked out more explicitly?
- The trivial vector bundle is flat, so shouldn't every connection be the flat connection?
Best Answer
Your work is good.