Future value formula is:
$A=P \cdot (1+\frac{r}{m})^{m \cdot t}$
where,
- $A$ is resulting amount
- $r$ is annual interest
- $P$ is present value
- $n$ is number of compound periods per year
- $t$ is time (in years)
And, exponential growth function is:
$P(t) = P_0 \cdot e^{k \cdot t}$
The question is:
A retirement account is opened with an initial deposit of $8,500 and earns 8.12% interest compounded monthly. What will the account be worth in 20 years? What if the deposit was calculated using simple interest? Could you see the situation in a graph? From what point one is better than the other?
So to calculate the account worth in 20 years with exponential growth formula:
$P_0$ is $8,500$ and $k$ is $0.812$, months in 20 years is $P(240)$ and so:
for the account worth in 20 years is:
$P(240)=8500 \cdot e^{0.812 \cdot 240} = 3.67052\dots E88$
After calculating with future value formula, the answer is different:
$A = 8500 \cdot (1+\frac{0.812 \cdot 12}{12})^{12 \cdot 20} = 7.71588\dots E65 $
I see different values when I calculate with exponential growth functions and future value formula.
How to achieve this calculation correctly with exponential growth function? Is it possible?
Best Answer
If I understand the notation in your question, I see a couple of items that seem they should be addressed:
The annual interest rate is $8.12$% which is $r=0.0812$, not $r=0.812$. Also, usually when interest rates are given, they generally refer to "annual" or "yearly" rates.
In the future value calculation, you don't need to multiply $0.0812$ by $12$, because this is already the annual interest rate.
With the above two modifications, one has:
$$ A=8500\left(1+\frac{0.0812}{12}\right)^{12 \cdot 20}=42888.18 $$
I believe to compute the "simple interest" values, one uses the formula:
$$ A_{simple}=8500\left(1+0.0812 \cdot 20\right)=22304 $$
More details here: https://en.wikipedia.org/wiki/Compound_interest#Calculation
I hope this helps.