Commutativity of multiplication for natural numbers (Terence Tao’s Analysis I exercise 3.6.5)

real-analysis

Exercise 3.6.5: Let $A$ and $B$ be sets. Show that $A\times B$ and $B\times A$ have equal cardinality by construction an explicit bijection between the two sets. Then use Proposition 3.6.14 (the one about the cardinal arithmetic) to conclude an alternative proof of Lemma 2.3.2 (this lemma proves the commutativity of multiplication).

The bijection is quite easy. But I've no idea why is he asking me to prove a property of multiplication with the cardinality of cartesian products. He defined the natural numbers and its operations with the Peano axioms, no with cardinality, so Tao hasn't really provided a construction of the naturals using only set theory.

What's the point of the exercise? Am I supposed to provide this construction, define the multiplication operation and then prove it or am I missing something?

Best Answer

Following the hint you're given for 3.6.14, I see:

(e) Let $X$ and $Y$ be finite sets. Then Cartesian product $X \times Y$ is finite and $\#(X \times Y ) = \#(X) \times \#(Y )$.

So if you have sets $A,B$ with $|A|=n$ and $|B|=m$, $|A\times B|=n\times m$.

Using exercise 3.6.5, one would also see $|A\times B|=|B\times A|=m\times n$, proving $n\times m = m\times n$ in a different way.

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