A farmer raises sheep and chickens at his farm. The number of sheep is $\frac{1}{3}$ the number of chickens. There are $96$ fewer sheep legs than chicken legs. How many sheep are there at the farm?
My work:
Number of sheep = $S$
Number of Chickens = $C$
We know that there is one third of sheep than chickens. so, $\frac{1}{3}S = C$
We know that there are 96 fewer sheep legs than chicken leg. so, $2C = 4S – 96$
I got stuck here.
Best Answer
You need to change your first equation. If the number of sheep is $\frac{1}{3}$ the number of chicken then $3S = C$.
Also in your second equation, the $-$ needs to be a $+$ because if there are fewer sheep legs than chickens then you'll need to add 96 on the sheep value.
Then combine the equations and you'll get the answer.