Are algebraic varieties strictly more general than (differentiable) manifolds

algebraic-geometrydifferential-geometrysmooth-manifolds

I have read that every non-singular algebraic variety is a smooth manifold. However, I was wondering if every smooth manifold can be expressed as a non-singular algebraic variety, or even just a general algebraic variety; such that algebraic varieties are a strict generalization of manifolds.

If not, does not restricting algebraic varieties to be defined in terms of polynomial equations allow for a generalization?

(Any references on the relation of varieties and manifolds, and any practical use of such a relation, would be appreciated, as I'm new to algebraic geometry. Thanks!)

Best Answer

The classes of varieties and manifolds have nontrivial intersection, but neither one contains the other. A complex projective variety can have singularities which would disqualify it from being a complex manifold. If it is nonsingular, then using the Jacobian criterion we see that we get a complex manifold. For the converse, if we can holomorphically embed our manifold in $\Bbb{P}^n$ as a closed subset then by Chow's Lemma it can be given the structure of an algebraic variety.

Of course, there are complex manifolds that are not algebraic. For instance the Hopf Surfaces $(\Bbb{C}^2\setminus \{0\})/\Gamma$ with $\Gamma$ a discrete group acting freely admit no Kähler metric and cannot be projective.

Actually, Serre's GAGA paper gives a way to translate between analytic geometry and algebraic geometry in the complex case. However, the suitable "analytic" notion of algebraic variety is an "analytic space" which is like a complex manifold but allowing for singularities.

Once we stop working over $\Bbb{C}$, we notice that algebraic varieties make sense over any field $k$ whereas the notion of manifold pretty much needs one to use $\Bbb{R}$ or $\Bbb{C}$. (Apparently there are analogues of manifolds over $\Bbb{Q}_p$ but I don't know much about that.) So, the notion of variety is much more general in that being cut out by polynomial equations makes sense over any ring let alone a field; varieties are more "algebraically general" whereas manifolds are more general in that over $\Bbb{R}$ and $\Bbb{C}$ there are many functions that are smooth/holomorphic but not polynomial.

Related Question