I am confused about the following matter (I come to a conclusion which is obviously wrong)
- if every real-valued function is a pointwise limit of a sequence of simple functions, e.g.
\begin{equation*}
f_n(x) = \left\{ \frac{j}{2^n} : j\in \mathbb{N}\cap [0,2^{2n}] \text { and } \frac{j}{2^n} \leq f(x) \right\}
\end{equation*} - and if simple functions are Lebesgue-measurable
- and if pointwise limit of Lebesgue-measurable functions is again Lebesgue-measurable
then does that mean that every real-valued function is Lebesgue-measurable?
Best Answer
The second statement is wrong. Consider the characteristic function of a set which is not Lebesgue measurable. The construction of a non-measurable set is classical. For instance, see https://www.math.purdue.edu/~zhang24/NonMeasurableSet.pdf